I have 25 .txt files that I would like to print. They are named 1.txt, 2.txt and so on. How can I do this?
I assume that "lpr *.txt" isn't suitable, either because there are other .txt files that you don't want to print or because you want the jobs to come out of the printer in a specific order.
You could do something like this:
lpr [1-9].txt 1[0-9].txt 2[0-5].txt
Or perhaps even:
lpr `ls *.txt | sort -n`
Too much typing? Assuming a current Bash, you can do:
lpr {1..25}.txt
That braces trick is even more powerful than that; see Bash 3.00 brace expansion.
Maybe you want some visual clue as to what's happening because it's 250 files, not 25. In that case, a loop will do it. You could use:
for i in {1..25}
do echo "Now printing $i.txt"
lpr $i.tx
done
or
x=1;while [ $x -lt 26 ]; do echo "Now printing $x.txt;lpr $x.txt; x=$((x+1));done
For conditions where it isn't ".txt" but something like file25foo, use "file${x}foo".
When it gets even more complicated, Bash extended globbing can be useful:
shopt -s extglob lpr !([A-z]*.txt)
That prints everything that doesn't match [A-z]*.txt.
Test out patterns with "echo" before wasting a bunch of paper:
$ echo +(1*|3*) 1.txt 10.txt 11.txt 12.txt 13.txt 14.txt 15.txt 16.txt 17.txt 18.txt 19.txt 3.txt
Let's not forget where you want to add a title or whatever:
for in in {1..25}
do
(echo " This is $i.txt";cat $i.txt) | lpr
done
And of course we could get MUCH fancier if desired.
If your script is expecting to find certain files but does not, what happens?
for i in *.foo do lpr $i done
That spits back '*.foo' and lpr would complain:
lpr: Error - unable to access "*.foo" - No such file or directory
That might be annoying. You could suppress stderr:
for i in *.foo do lpr $i 2>/dev/null done
Or just avoid missing files:
for i in *.txt *.foo do if test -e $i then lpr $i fi done
A shorter version:
for i in *.txt *.foo do test -e $i && echo $i done
What if some of those files were not text? That could make a mess of your printer output tray, couldn't it? There's a "file" command that could help and also avoid wasting time on empty files.
for i in *.txt *.foo do test -n "`file $i | grep text`" && lpr $i done
That avoids everything but 1.txt and 10.txt in this directory:
$ file * 1.txt: ASCII text 10.txt: ASCII text 11.txt: empty 12.txt: JPEG image data, EXIF standard 13.txt: empty 14.txt: empty 15.txt: empty 16.txt: empty 17.txt: empty 18.txt: empty 19.txt: empty 2.txt: empty 20.txt: empty 21.txt: empty 22.txt: empty 23.txt: empty 24.txt: empty 25.txt: empty 3.txt: empty 4.txt: empty 5.txt: empty 6.txt: empty 7.txt: empty 8.txt: empty 9.txt: empty
Putting some of these ideas together could result in a pretty powerful script that would do exactly what you want in every case. However, I will add this: once it gets even slightly complicated, I turn to Perl. It's not that you can't do complex jobs with shell scripts, but that twisting around shell script limitations can get quite painful. I like to avoid that pain.
More Articles by Anthony Lawrence - Find me on Google+ 2013-08-01
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